eigenvectors: vectors that are stretched or squashed during the transformation
eigenvalue: the values of stretching or squashing during the transformation, can be negative or not exist
xz z
solving
finding eigenvec and eigenval of matrix A comes down to solving for Ξ» (scaling value - eigenvalues) and v (scaling vectors - eigenvectors), in Av=Ξ»v
to solve the eigenvalue Ξ», solve: (AβΞ»I)v=0,
knowing that we dont want the eigenvectors v = 0, the matrix to solve is (AβΞ»I)=0, which looks like this
fundamental behind (each bullet points are following inferences):
equation (AβΞ»I)v=0β the product of matrix with nonzero vector v = 0
If the linear transformation (A - Ξ»I) squishes the space into a lower dimension β the transformation must have a nontrivial null space
The null space of the transformation (AβΞ»I) is the set of all vectors v that satisfy the equation (AβΞ»I)v=0
The equation (AβΞ»I)v=0 implies that the linear transformation (AβΞ»I) maps every vector v to the zero vector β the transformation is not injective β det = 0 (see injection and determinant relation)
it goes down to finding det(AβΞ»I)=0
eigenvalues: Ξ»
eigenvectors: replace Ξ» with the result found β find v1, v2 vectors